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kimmgamjja
[Java] Exception>java.lang.NumberFormatException++Exception Message>For input string: "10000000000"++Stack Trace>java.lang.NumberFormatException: For input string: "10000000000"
기존 자바 소스 list = list.stream().sorted((o1, o2) -> Integer.valueOf(o1.get("NUMBER").toString()).compareTo(Integer.valueOf(o2.get("NUMBER").toString())) ).collect(Collectors.toList());list 를 stream().sorted() 를 이용해 정렬해주려다가 Exception>java.lang.NumberFormatException++Exception Message>For input string: "10000000000"++Stack Trace>java.lang.NumberFormatException: For input string: "10000000000" 이러한 에러가..
공부/Java
2025. 2. 14. 15:26